问题：

如何将table相同内容的同列表格进行合并

解决办法：

(($) {
    $..({
        : (colIdx) {
            .(() {
                that$().((row) {
                    $(+ colIdx + ).().((col) {
                        (that != && $().() != && $().() == $(that).()) {
                            = $(that).()(== ) {
                                $(that).()= $(that).()}
                            = Number() + $(that).()$().()} {
                            that = }
                    })})})}
    })})()